Accelerated test design and analysis of rolling bearings based on the principle of equivalence
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摘要:
针对越来越多的滚动轴承具有高可靠、长寿命的特点,提出一种基于等效原理的滚动轴承加速试验设计与评估方法。首先根据等效原理,建立了加速应力和正常应力之间的寿命分布关系式;其次,针对工程中常见的定时无失效、定时截尾和定数截尾3种数据类型,推导出了轴承剩余强度分布形状参数的估计方法;随后,分别推导出滚动轴承在给定可靠度下的加速应力水平和试验截止时间和在给定应力下的轴承可靠度与可靠寿命的单侧置信下限;最后,结合某关节轴承工程实例进行验证分析,结果表明:该方法计算出的正常应力水平下寿命和可靠度单侧置信下限分别为293.94 h和0.945,与实际的300 h和0.95吻合较好,为滚动轴承加速试验设计与评估提供有力的理论支撑。
Abstract:In view of the characteristics that more and more rolling bearings have high reliability and long life, a method based on the principle of equivalence was proposed for the accelerated test design and assessment of rolling bearings. Firstly, the relationship between the accelerated stress and the normal stress in terms of life distribution was established based on the principle of equivalence. Secondly, the estimation method of the shape parameters of the residual strength distribution of the bearing was individually given for the three common data types in the engineering, including zero-failure data, type-I and type-Ⅱ censored data. Subsequently, the accelerated stress levels and test cut-off times for rolling bearings at a given reliability, as well as the one-sided lower confidence limits for the bearing reliability and reliable life at a given stress, were derived, respectively. Finally, a validation analysis was conducted using a specific bearing engineering case study. The results indicated that the calculated lower one-sided confidence limits for life and reliability at normal stress levels were 293.94 h and 0.945, closely aligning with the actual values of 300 h and 0.95. This could strongly support the design and evaluation of accelerated testing for rolling bearings.
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表 1 关节轴承试验结果
Table 1. Test results of joint bearing
工况 编号 失效寿命/h $ {S_0} = 10 $ kN Bearing 1-1 462 Bearing 1-2 756 Bearing 1-3 602.28 Bearing 1-4 619.56 $ {S_{\text{t}}} = 25 $ kN Bearing 2-1 224.2 Bearing 2-2 280.33 Bearing 2-3 320.62 Bearing 2-4 361.25 表 2 计算结果
Table 2. Calculation results
工况 寿命/h 可靠度 $ {S_{\text{t}}} = 25 $ kN 325.6 0.966 $ {S_0} = 10 $ kN 293.94 0.945 -
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