Thrust stand model analysis and thrust positioning based on screw algebra
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摘要:
基于旋量理论和变形位移协调关系,对八分支正交盒式测力台架进行了旋量建模、模型求解、误差补偿和推力定位方面的研究。从台架的载荷偏心和测力耦合两大特点出发,建立了台架的旋量模型,并结合分支变形约束关系推导出辅助模型求解的约束方程。数值算例和仿真表明,旋量模型及约束方程的最大相对误差为9.147‰。基于测力单元变形与台架位移之间的协调关系,建立了误差补偿模型。数值算例和仿真表明,分力的最小补偿量为78.03%。此外,针对矢量推力定位的不确定性问题,通过旋量理论的Poinsot中心轴定理明确了其原因,即忽略了合力中纯力偶的影响。解析法表明,质心偏移对矢量推力不确定的影响为线性。
Abstract:The screw theory and coordination between deformation and displacement were applied to research the octagonal orthogonal box-type thrust stand in screw modeling, model solving, error compensation, and thrust positioning. Screw model of the stand was established based on the two major characteristics of load eccentricity and force coupling. And constraint equations for model solution were derived based on the branches deformation constraint relationship. Numerical examples and simulations showed that the maximum relative error of the screw model was 9.147‰. An error compensation model was established based on the coordinated relationship between the branches deformation and the stand displacement. Numerical examples and simulations showed that the minimum compensation for force was 78.03%. The Poinsot’s central axis theorem of the screw theory was used to clarify the uncertainty of vector thrust positioning, which was caused by ignoring the influence of pure couple in the resultant force. The analytic method indicated that the effect of mass center offset on vector thrust uncertainty was linear.
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Key words:
- thrust stand /
- deformation compatibility /
- screw algebra /
- stand design /
- thrust positioning
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表 1 载荷信息表
Table 1. Load information table
分力 方向/m 作用点/m 分力数值 Fx/kN (1, 0, 0) (0, 3.36, 0) 150 Fy/kN (0, 1, 0) (0, 3.36, 0) −100 Fz/kN (0, 0, 1) (0, 3.36, 0) 50 Mz/(kN·m) (0, 0, 1) (0, 3.36, 0) −50 表 2 重力信息表
Table 2. Gravity information table
结构 重力方向/m 重心坐标/m 质量/kg 模型 (0, −1, 0) (0, 3.36, 0) 5000 支架 (0, −1, 0) (0, 2, 0) 5000 动架 (0, −1, 0) (0, 0.6, 0) 2000 表 3 测力单元信息表
Table 3. Force cell information table
i $ {{\boldsymbol{r}}_{{\mathrm{s}}i}} $/mm $ {{\boldsymbol{t}}_{{\mathrm{s}}i}} $/ mm $ {{\boldsymbol{s}}_{{\mathrm{s}}i}} $/m 1 (− 1360 , 100, −320)(− 1360 , 635, −320)(0, 1, 0) 2 (− 1360 , 100, 320)(− 1360 , 635, 320)(0, 1, 0) 3 ( 1360 , 100, 320)( 1360 , 635, 320)(0, 1, 0) 4 ( 1360 , 100, −320)( 1360 , 635, −320)(0, 1, 0) 5 (−470, 390, −300) (−40, 390, −300) (1, 0, 0) 6 (470, 390, 300) (40, 390, 300) (−1, 0, 0) 7 (− 1100 , 515, 180)(− 1100 , 515, −180)(0, 0, −1) 8 ( 1100 , 515, −180)( 1100 , 515, 180)(0, 0, 1) 表 4 测力模型计算结果
Table 4. Force measurement model calculation results
编号 力/N 相对
误差/‰理论数值 仿真数值 差值 1 147817.37 − 148159.50 − 342.1259 2.309 2 − 74448.25 74782.77 334.5158 4.473 3 − 256617.37 256982.63 365.2618 1.421 4 − 34351.75 34040.37 − 311.3798 −9.147 5 75000.00 − 75049.34 − 49.3374 0.657 6 − 75000.00 75044.18 44.1807 0.589 7 − 25000.00 25175.27 175.2674 6.962 8 25000.00 − 24892.22 107.7764 −4.330 表 5 载荷测量结果
Table 5. Result of load measurement
$ {{\boldsymbol{W}}_{{\mathrm{lg}}}} $/N $ ({{{\boldsymbol{G}}_{\mathrm{s}}}{{\boldsymbol{f}}_{\mathrm{s}}} - {{\boldsymbol{W}}_{{\mathrm{lg}}}}} ) $/N $ ( {{\boldsymbol{G}}_{\mathrm{s}}'{\boldsymbol{f}} - {{\boldsymbol{W}}_{{\mathrm{lg}}}}} ) $/N $ {\boldsymbol{E}} $ 150000 − 142.5034 31.2895 − 0.2196 − 100000 186.7216 2.4000 0.0129 50000 − 118.4333 6.4352 − 0.0543 169003.17 − 47.0292 51.8225 − 1.1019 1567.5947 331.7391 − 59.6066 − 0.1797 − 554233.5 13.9714 − 64.7990 − 4.6380 表 6 合力状态表
Table 6. State of resultant force
序号 合力 合力矩 力与力矩位置关系 刚体受力状况 1 ≠0 =0 过原点纯力 2 =0 ≠0 纯力偶 3 =0 =0 平衡 4 ≠0 ≠0 垂直 不过原点纯力 5 ≠0 ≠0 平行 螺旋状态 6 ≠0 ≠0 既不垂直也不平行 不过原点纯力和纯力偶 -
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